Hi, On Wed, Aug 03, 2005 at 11:21:35AM +0200, Tomas Davidek wrote:
> * I store all the scripts in a tarball, so all I have to do is to unpack > them in the respective directory during the "make install" stage (i.e. > no compilation is needed). I succeeded to do so by introducing the > following Makefile: > ------------- > clean: > rm -fr debian/ucjf-security > > install: > cd $(DESTDIR) ; \ > tar -xvzf ../../../ucjf-security_1.0.1.orig.tar.gz > -------------- > It works, however I would expect that the path to a tarball can be > specified in a better way (is there any variable containing the top > directory name ?). Also, the version should not be hardcoded there, I > guess. Is there a way to tell the Makefile to use the latest > version/same version as is the name of the working directory ? if the debian/rules file is executed then the orig tarball is already unpacked (with the diff applied if it isn't a native package). Why untar again? Just place the files with "cp" where you want them to be. > * since the pakcage contains only few shell scripts, it should be > architecture-independent. Therefore, I specified "Architecture: any" in > the "control" file and also moved all the action in the "rules" file > into the binary-indep section (see attachment).... However, the > resulting package still contains in its control file the item > "Architecture: i386" (which is where the package is produced, but ....). this should be "Architecture: all", not any. -Ralf. -- -- To UNSUBSCRIBE, email to [EMAIL PROTECTED] with a subject of "unsubscribe". Trouble? Contact [EMAIL PROTECTED]
