On Wed, 07 Mar 2001 13:26:35 -0500, [EMAIL PROTECTED] wrote: >> (1) >> Have one init script and have this init script be invoked in two >> places. > >Yuck.
ack ;) >> (2) >> Have two completely different init scripts. I rejected this because >> both scripts aren't that much different and there would be much >> redundancy. > >Then have three scripts. Put the common common code into a third script >which is not called directly by init, but have the two init scripts call >the third script. This avoids redundancy and is quite clear, I think. But it is as well yucky. Where should the script with the common code be located? /etc/init.d as well? Greetings Marc -- -------------------------------------- !! No courtesy copies, please !! ----- Marc Haber | " Questions are the | Mailadresse im Header Karlsruhe, Germany | Beginning of Wisdom " | Fon: *49 721 966 32 15 Nordisch by Nature | Lt. Worf, TNG "Rightful Heir" | Fax: *49 721 966 31 29
