Jacob Adams writes ("sct public domain"):
> Firstly, the license of sct consists of one line:
> /* public domain, do as you wish
Seems like a clear enough intent to dedicate to the public domain,
along with a permission to deal freely. So yes.
> Secondly, sct.c contains these lines:
>
> /* cribbed from redshift, but truncated with 500K steps */
> static const struct { float r; float g; float b; } whitepoints[] = {
> { 1.00000000, 0.18172716, 0.00000000, }, /* 1000K */
>
> redshift is a program that does the exact same thing but with more code.
> This part is clearly copied and so does sct need to be GPL because it
> borrows code from redshift? This is data and so it could be not
> copyrightable but I don't know.
Is the formatting from redshift too ? If not then I think the r and b
values are probably fixed and the only thing remaining is the g value.
Not sure if that's enough to make it copyright. It might depend on
what exactly those values are. I don't know enough about colour
spaces and whatnot to say for usre.
You could always ask the relevant redshift copyrightholder and see
what they think.
Ian.
