Glenn Maynard wrote:
I would assume that the same applies to Kaffe.
Well, if gcc has an explicit "output of this program isn't subject to the GPL", even though the FSF says[1] that the output of a program is generally not subject to the terms of the program outputting it anyway, that probably means that it *might* be arguably subject to it (depending on how much of gcc ends up in gcc's output), and the FSF is giving an explicit exception to eliminate any doubt.
Irrelevent. Kaffe is an interpreter, it's not a compiler like gcc. Kaffe creates no output of its input.
cheers, dalibor topic
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