I just realized I should make a clarification... according to newer
standards, the setup below to create two subnets would work.
But, according to some older standards, to create two usable subnets
from 192.168.1.x, you would have to use 255.255.255.192 as the subnet
mask, and you would actually end up with 4 groups, with 62 usable IP
address in each. But the older standards don't allow use of the first
and fourth groups...
Subnetwork 1:
192.168.1.1 - 192.168.1.63
Subnetwork 2:
192.168.1.64 - 192.168.1.127
Subnetwork 3:
192.168.1.128 - 192.168.1.191
Subnetwork 4:
192.168.1.192 - 192.168.1.255
David Woyciesjes wrote:
>
> criggie wrote:
> >
> >
> > BTW the answer would be to subnet, to use 0-127 on one side and 128-255
> > on the other side, with a netmask of 255.255.255.127
> >
> > --
>
> Actually, that subnet mask would be 255.255.255.128. (In binary -
> .10000000)
>
> Subnetwork 1:
> Network address - 192.168.1.0
> Broadcast address - 192.168.1.127
> IP address range - 192.168.1.1 - .126
>
> Subnetwork 2:
> Network address - 192.168.1.128
> Broadcast address - 192.168.1.255
> IP address range - 192.168.1.129 - .254
>
> Hope all this info we're providing helps...
>
> --
--
--- Dave Woyciesjes
--- ICQ# 905818
