tag 423156 + moreinfo
thanks
Jens-Wolfhard Schicke writes:
> Package: libstdc++6-4.1-dev
> Version: 4.1.2-6
>
> In Line 246ff, it says:
>
> explicit
> codecvt(state_type& __enc, size_t __refs = 0)
> : __codecvt_abstract_base<intern_type, extern_type,
> state_type>(__refs)
> { }
>
> Using -Wall, one gets an "unused parameter" warning for __enc.
>
> One solution would be to remove the __enc, and just leave the type.
> (However I don't know where the encoding information is passed to then...)
please provide a testcase, a simple
#include <locale>
#include <cstdlib>
#include <string>
#include <ext/codecvt_specializations.h>
doesn't show any warning.
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