Hello collegues, I don't understand dpkg's version compare algorithm: ([EMAIL PROTECTED]) /var/debian/unstable/binary-i386/math$dpkg --compare-versions 1.15 lt 1.2-1; echo $? 1 ([EMAIL PROTECTED]) /var/debian/unstable/binary-i386/math$dpkg --compare-versions 1.15 lt 1.20-1; echo $? 0 ([EMAIL PROTECTED]) /var/debian/unstable/binary-i386/math$dpkg --version Debian Linux `dpkg' package management program version 1.4.0.19 (i386 elf). Copyright 1994-1996 Ian Jackson, Bruce Perens. This is free software; see the GNU General Public Licence version 2 or later for copying conditions. There is NO warranty. See dpkg --licence for details. ([EMAIL PROTECTED]) /var/debian/unstable/binary-i386/math$
Why is 1.15 > 1.2 ? Is it necessary to fill in trailing zeroes? David -- David Frey (51F35923114FC864 7D05FF173C61EFDE) Those who do not understand Unix are condemned to reinvent it, poorly. -- Henry Spencer -- TO UNSUBSCRIBE FROM THIS MAILING LIST: e-mail the word "unsubscribe" to [EMAIL PROTECTED] . Trouble? e-mail to [EMAIL PROTECTED] .
