James Clarke wrote: > I believe it's actually (3C2)*(2/3)^16 - (3C1)*(1/3)^16 ~= 0.46% (the > subtracted value is negligible).
Thanks :)
> > It will also FTBFS if it generates the exact same random string, but
> > that seems a little more unlikely.
>
> P = (1/3)^16 = 2.3e-8 or 0.0000023%, which isn't quite as absurdly small
> as you might think.
Ah, but a little more unlikely than 0.46%… :)
Regards,
--
,''`.
: :' : Chris Lamb
`. `'` la...@debian.org / chris-lamb.co.uk
`-
