Hi again, Manoj. On Oct 18 2008, Rogério Brito wrote: > On Oct 18 2008, Manoj Srivastava wrote: > > On Sun, Aug 31 2008, Rogério Brito wrote: > > > Is there anything that I can do to make kernel-package generate the > > > uImage (for booting with uBoot) that I need? > > > > but a valid subarch under the same architecture, right? --subarch > > might be the way to go, but may need some fixes. > > I really don't know which subarch we should be calling here.
It seems that the files needed are in arch/powerpc/platforms/embedded6xx/ > > This also seems to be a special case: there is a specific target > > that can be invoked. Does running make all also invoke uImage? > > I will have to test this. I will follow up in a sec. Yes, it does. > > If not, we need to tell kernel-package to not run bzImage, but > > this instead. Does uImage still produce a vmlinuz? > > I also don't know this bug I can answer this in a moment. "make all" creates: * a vmlinux in the root directory of the kernel tree * a zImage in arch/powerpc/boot/ * a uImage in arch/powerpc/boot/ Regards, Rogério Brito. -- Rogério Brito : [EMAIL PROTECTED],ime.usp}.br : GPG key 1024D/7C2CAEB8 http://www.ime.usp.br/~rbrito : http://meusite.mackenzie.com.br/rbrito Projects: algorithms.berlios.de : lame.sf.net : vrms.alioth.debian.org -- To UNSUBSCRIBE, email to [EMAIL PROTECTED] with a subject of "unsubscribe". Trouble? Contact [EMAIL PROTECTED]
