I thought if that, but left it as [ -z "$?" -o "$?" == 0 ] just in case $? was
not defined. I would guess that is impossible with bash, but I am not sure
about other shells.
I am also not sure about "0" vs 0, my understanding is that the quotes are
removed before the comparison, so it doesn't matter in this case.
I am not sure about the = vs ==. == appears to work in bash, but I don't know
which is more portable.
Thanks,
-Jim
On Tuesday 04 April 2006 14:55, sean finney wrote:
> hi jim,
>
> On Tue, Apr 04, 2006 at 12:50:35PM -0400, Jim Jensen wrote:
> > --- /etc/init.d/nagios2 2006-04-04 10:35:07.783457264 -0400
> > +++ /etc/init.d/nagios2~ 2006-02-12 05:22:24.000000000 -0500
> > @@ -181,7 +181,7 @@
> > restart)
> > log_daemon_msg "Restarting $DESC" "$NAME"
> > stop
> > - if [ -z "$?" -o "$?" == 0 ]; then
> > + if [ -z "$?" ]; then
>
> hrm... shouldn't that be
>
> if [ "$?" = "0" ];
>
> ?
>
> sean
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