On 10/26/2017 09:50 AM, Yiyang Zhang wrote:
It seems to me that both ways are fine. Is there any particular reason
that we prefer one than the other?
Yes, both ways are correct.
But you will need a constraint object to eliminate hanging node
constraints and boundary values from the newton_update equation before
you solve for the newton update, and these constraints need to be
homogeneous.
Since the constraints object you show for your second approach, that
means that you have to keep two constraints objects around. That's more
work, more memory, etc, so people usually prefer approach one.
Best
W.
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Wolfgang Bangerth email: bange...@colostate.edu
www: http://www.math.colostate.edu/~bangerth/
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