where x component of vector_RHS is -(grad_psi)_y / x and y component is
(grad_psi) / x (here psi is the another calculated scalar solution)
So, I refer to "class AdvectionField : public TensorFunction<1,dim>" in
step-9.cc to form the vector_RHS
You're approaching this the wrong way. The Function<dim> and
TensorFunction<dim> classes are intended to represent functions that only
depend on x,y or x,y,z. But in your case, your right hand side depends on the
solution itself.
I think you should look into how step-15 builds a right hand side that depends
on the solution. It will probably be something like this:
FEValuesExtractors::Scalar scalar_solution(0);
std::vector<Tensor<1,dim>> solution_gradients (n_q_points);
for (cell=...)
{
fe_values.reinit(cell);
fe_values[scalar_solution].get_function_gradients (solution,
solution_gradients);
for (q=...)
{
for (i=...)
for (j=...)
cell_matrix(i,j) += ...
Tensor<1,dim> rhs;
Point<dim> q_point = fe_values.quadrature_point(q);
rhs[0] = solution_gradients[q][1] / q_point[0];
rhs[1] = solution_gradients[q][0] / q_point[0];
for (i=...)
local_rhs(i) = fe_values[scalar_solution].value(i,q) *
rhs *
fe_values.JxW (q);
}
...
Best
W.
--
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Wolfgang Bangerth email: bange...@colostate.edu
www: http://www.math.colostate.edu/~bangerth/
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