On 08/19/2016 04:23 PM, David F wrote:
P.S.: I tried to simply repeat the process to re-apply the BCs with a new
value using the same matrix, but I get always the first BCs I apply (I think
because once I apply it, the matrix knows it has been already condensed and
ignores the next calls).
Yes. What you need to do is in every time step copy the matrix you have
previously assembled into a new matrix, call apply_boundary_values() to this
matrix and your current right hand side, and then solve the linear system.
This way, you always start from the same matrix.
I think one of steps 23, 24, 25, 26 does this.
Best
Wolfgang
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Wolfgang Bangerth email: bange...@colostate.edu
www: http://www.math.colostate.edu/~bangerth/
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