Is there some reason the aspect ratio can't be specified with two
input boxes:  x : y ?

Then the person could imput 16 : 9   or   1.7777 : 1   or  8 : 4.5
-- however they preferred.  [ And if they wanted it rotated, then
9 : 16 .]

Personally, I'd prefer the flexibility over the convenience.

--alan

* August Schwerdfeger (aug...@schwerdfeger.name) [181116 14:22]:
* Subject: Re: [darktable-dev] Feature request (Cropping module GUI):
> The problem with selecting these integers based on commonly-used aspect
> ratios, is that the only real use for this feature would be in "freehand"
> mode when cropping to an *unusual* aspect ratio; the common ones like 16:9
> are represented in the "aspect" combo box and it is much easier to select
> the "16:9, HDTV" option to constrain the ratio.
> 
> --
> August Schwerdfeger
> aug...@schwerdfeger.name
> 
> On Fri, Nov 16, 2018 at 2:51 PM Jan Ingwer Baer <jib...@web.de> wrote:
> 
> > On 16-Nov-18 18:26, Heiko Bauke wrote:
> > > Hi,
> > >
> > > Am Freitag, 16. November 2018 schrieb Jan Ingwer Baer:
> > >> If DT shows the aspect ratio it should try to find the nearest integral
> > >> fraction (of course with values below 30) like 3:2, 16:9, ...
> > >>
> > >>
> > >> For your exampel it should show 8.2:5, or it should use one of the
> > >> common denominators x:2, x:3, x:4, x:9 ...
> > >
> > > I don't think that this is a good idea, as the user can not know how
> > close the actual aspect ratio is to the approximate value that is indicated
> > in the UI.
> > >
> > > Heiko
> > >
> > Of course DT should not round, but it should show the Ratio with an
> > integer for the small-side. For me showing 8.2/5 or 3.28/2 (with the
> > pixel-ratio of the OP) is much more meaningful then 1.62/1. I think it
> > should be possible to select a usable integer numerator/denominator
> > based on the fractional ratio.
> >
> > If the user wants to create a crop with one of the common aspect ratios
> > showing it as simple float makes it very challenging to find the right
> > values. For example : The user wants to create a crop with 16/9.
> > Displaying the aspect ratio as 1.77/1 is not a big help.
> >
> > The challenge is to find the right integer. My idea is to define ratio
> > ranges for selection :
> >
> > 1.2 - 1.4 : set denominator to 3 gives  3.6/3 -  4.2/3 ( ~4/3)
> > 1.4 - 1.6 : set denominator to 2 gives  2.8/2 -  3.2/2 ( ~3/2)
> > 1.6 - 1.9 : set denominator to 9 gives 14.4/9 - 17.1/9 (~16/9)
> >
> >
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> >
> 
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