Haojun Bao wrote:
grischka <gr1...@googlemail.com> writes:If I compile this snippet: #include <stdio.h> int main (int argc, char **argv) { int i; for (i = 0; i < argc; ++i) printf("argv[%d] %s\n", i, argv[i]); return 0; } with cygwin GCC and then run it from CMD prompt: C:\cygwin\home\me> test \"stuff\" it prints this: argv[0] test argv[1] \stuff" Is that expected? I'm aware that there is some conversion going on and that it's meant to work from a cygwin shell really, but still.Yes, it's expected. The 1st `\' is not special to windows, so it get printed, the 1st `"' start a quote and it's removed, the 2nd `\' is in a quoted string, so it's removed but the 2nd `"' following it gets printed. And you didn't end your quoted string properly.
Indeed, it looks like that \ can escape " within "..." but not outside. That is per se logical, just that such logic doesn't seem to exist neither in windows nor in posix. So I still wonder how it comes into play.
You can also try test "x""y", it should print `argv[1] x"y'
That looks more familiar like if it came from windows. Then again, cygwin also parses "x:y""z" into x:y\z. Hm. Is this now because me didn't quote properly or is it an artifact from the posix/windows mix or is it something clever, under circumstances? --- gr -- Problem reports: http://cygwin.com/problems.html FAQ: http://cygwin.com/faq/ Documentation: http://cygwin.com/docs.html Unsubscribe info: http://cygwin.com/ml/#unsubscribe-simple
