> It's irrelevent what the name of the .exe is. As > Igor already said, > even if a third party packages a cygwin1.dll that > has simply been > renamed, it will still have the same shared memory > name, so that if the > two DLLs are ever loaded at the same time they will > clash. This is > exactly what the error message you're getting > indicates -- that you have > two incompatible Cygwin libraries on your system > somewhere, even if one > of them has been renamed to something you don't > recognise. >
Brian,
I have uninstall OpenSSH and every software that was
including cygwin1.dll (WinBoard, ...), and I obtain
the same message when I try to launch cygwin.
Pardon my insistance, I'm not familiar to the dll
mechanism, and I understand that the name in the
shared memory af a DLL instance does not correspond to
the dll filename, but if I rename a .dll file, how can
it be loaded again ?
Furthermore, I have, right now, just one and only one
cygwin1.dll, and it is the original one from the
latest release. So maybe another program has loaded
this dll from a totally different filename. Is there a
way to know which dll is loaded in memory and which
filename or program it is loaded from ?
I don't mean to bother, just trying to understand and
fix the problem as cygwin is a great tool and would
help me in what I'm doing.
Thx.
PS: attached my latest cygcheck output.
___________________________________________________________
To help you stay safe and secure online, we've developed the all new Yahoo!
Security Centre. http://uk.security.yahoo.com
cygcheck.out
Description: 3924260979-cygcheck.out
-- Unsubscribe info: http://cygwin.com/ml/#unsubscribe-simple Problem reports: http://cygwin.com/problems.html Documentation: http://cygwin.com/docs.html FAQ: http://cygwin.com/faq/
