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According to John Morrison on 5/8/2005 1:52 AM:
> On Fri, March 25, 2005 8:26 pm, Eric Blake said:
>
>>True enough. And that points out another bug - echo "$0" may fail if $0
>>starts with -, it should be echo -- "$0". Isn't portable shell
>>programming fun?
>
> Sorry that this has taken so long, but I'm just getting around to adding
> all the fixes emailed wrt /etc/profile. I tried the above, and it broke
> so I checked the man pages,
Serves me right for thinking that echo was standard when I typed my
original message, rather than me actually testing at the command line.
Yes indeed, POSIX requires that echo must interpret -- as a string
operand, rather than the standard interpretation of being an argument
separator.
> so, I'm afraid that echo -- "${0}" won't work.
>
This will work instead:
case `printf %s "$0" | /usr/bin/tr '[:upper:]' '[:lower:]'` in
bash | -bash | */bash )
[..]
- --
Life is short - so eat dessert first!
Eric Blake [EMAIL PROTECTED]
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