How about posting a simple test case. If you do so, I'll try and take a look.
-- Brian Ford Senior Realtime Software Engineer VITAL - Visual Simulation Systems FlightSafety International the best safety device in any aircraft is a well-trained pilot...
#include <stdarg.h> #include <pthread.h>
pthread_mutex_t printf_mutex;
void *thread_exec(); void myprintf(char *,...);
main()
{
pthread_t id1,id2;
char *s1="11111";
char *s2="22222";pthread_mutex_init(&printf_mutex,NULL);
pthread_create(&id1,0,thread_exec,(void *)s1);
pthread_create(&id2,0,thread_exec,(void *)s2); pthread_join(id1,NULL);
pthread_join(id2,NULL);}void *thread_exec(string)
char *string;
{
int i; for (i=0;i<10;i++)
myprintf("%s (%d)\n",string,i);pthread_exit(NULL); }
void myprintf(char *msg,...)
{
va_list arg;/* pthread_mutex_lock(&printf_mutex);*/
va_start(arg, msg);
vprintf(msg, arg);
va_end(arg);/* pthread_mutex_unlock(&printf_mutex);*/ }
When run, I get:
$ gcc t.c ; ./a.exe 11111 (0) 11111 (1) 11111 (2) 11111 (3) 11111 (4) 11111 (5) 11111 (6)11111 (6)
22222 (6)22 22222 (2) ( 22222 (3) 122222 (4))
22222 (5)11111 (8)
22222 (6)11111 (9)
22222 (7) 22222 (8) 22222 (9)
With the mutexes uncommented, I get:
$ gcc t.c ; ./a.exe 22222 (0) 22222 (1) 22222 (2) 22222 (3) 22222 (4) 22222 (5) 11111 (0) 22222 (6) 11111 (1) 22222 (7) 11111 (2) 22222 (8) 11111 (3) 22222 (9) 11111 (4) 11111 (5) 11111 (6) 11111 (7) 11111 (8) 11111 (9)
which is as expected.
For this simple test case, I was not able to get vprintf() to crash, but it does on my more complicated application (lots of parameters passed to vprintf()). I'm pretty sure it's not a bug in my application as putting in the mutex locking around the vprintf() stops the crashes.
Thanks again for your help.
- John
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