On 2024-11-06 08:30, Dimitry Andric via Cygwin wrote:
On 6 Nov 2024, at 16:11, Sebastian Feld via Cygwin <cygwin@cygwin.com> wrote:
How can I test in a /usr/bin/make Makefile whether I am running on a
32bit or 64bit Cygwin (not Windows kernel)?
Usually in a shell you use "uname -m", or with bash specifically, the $HOSTTYPE
variable.
However in GNU make you should be able to use the internal variable $(MAKE_HOST). On my Cygwin
installation, this gives the value "x86_64-pc-cygwin". Since I do not have any 32-bit
Cygwin installation, I cannot tell you what the exact value is, but my guess would be
"i386-pc-cygwin", or something like that.
Cygwin 32 (no longer supported) was i686-pc-cygwin as are Mingw cross-builds:
$ ls -1 /usr/bin/i*-gcc-[0-9]*
/usr/bin/i686-w64-mingw32-gcc-6.4.0.exe
/usr/bin/i686-w64-mingw32-gcc-7.4.0.exe
--
Take care. Thanks, Brian Inglis Calgary, Alberta, Canada
La perfection est atteinte Perfection is achieved
non pas lorsqu'il n'y a plus rien à ajouter not when there is no more to add
mais lorsqu'il n'y a plus rien à retirer but when there is no more to cut
-- Antoine de Saint-Exupéry
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