On 2010/01/19 8:06 PM, Eric Blake wrote: > Using -ansi generally says that you want the headers to expose ONLY the > interfaces mentioned in the C89 standard. But C89 did not describe > snprintf, hence your compilation failure.
Actually, it looks like -ansi means something slightly different when used in C++ mode. According to the gcc manual, -ansi in C++ mode is equivalent to -std=c++98 , which in English means "use the 1998 ISO C++ standard plus amendments". Googling "1998 ISO C++ standard", I was able to find something that looks like an official ISO document which covers this standard, and its <cstdio> library does _not_ mention snprintf(), just as you stated. Thus, it appears that in this case the Cygwin compiler's behaviour is correct (i.e. to treat snprintf as undefined under -ansi), while the Debian compiler has it wrong. Interesting! > In the meantime, either don't use snprintf without declaring it by hand, > or else don't use -ansi, since they are obviously not compatible in the > current state of the headers. Will do. Thanks for your time. -SM -- -- Problem reports: http://cygwin.com/problems.html FAQ: http://cygwin.com/faq/ Documentation: http://cygwin.com/docs.html Unsubscribe info: http://cygwin.com/ml/#unsubscribe-simple
