On Mon, Jan 4, 2010 at 1:40 PM, Jacob Jacobson wrote: > I am curious as to why this happened. > > I was at work yesterday and created a file. The name of the file > is created using the Cygwin date function. > > REV=$(date +rev-%b-%d-%g) > APPNAME="$1-$REV.img"
%g (and the four-digit version %G) is the year according to the ISO week-number calendar; each such year is always a whole number of weeks (364 or 371 days), starting on a Monday and ending on a Sunday. Specifically, the first week is always the one containing January 4th; as such, today is 2010W1-1, the first day of the ISO year, and yesterday was 2009W53-7, the last day of the previous ISO year. So you got what you asked for, even if that wasn't what you actually wanted. :) If you want the CE year according to the standard Gregorian calendar, use %y (2-digit) or %Y (4-digit). -- Mark J. Reed <markjr...@gmail.com> -- Problem reports: http://cygwin.com/problems.html FAQ: http://cygwin.com/faq/ Documentation: http://cygwin.com/docs.html Unsubscribe info: http://cygwin.com/ml/#unsubscribe-simple
