It appears that two EXEs can coexist (with the registry setting) but
only whichever one was so named first will be run:
$ cat > lower.c <<EOF
#include <stdio.h>
int main(void) { printf("I am a lower-case a\n"); return 0; }
EOF
$ cat > upper.c <<EOF
#include <stdio.h>
int main(void) { printf("I am an UPPER-case A\n"); return 0; }
EOF
$ gcc -o A.exe upper.c
$ gcc -o a.exe lower.c
$ ls
A.exe* a.exe* lower.c upper.c
# note that A.exe was created first
$ ./A.exe
I am an UPPER-case A
$ ./a.exe
I am an UPPER-case A
# Say what?
$ mv A.exe A2.exe; mv A2.exe A.exe
# now a.exe was there first, let's try again...
$ ./a.exe
I am a lower-case a
$ ./A.exe
I am a lower-case a
# Oh really?
$ cat > B <<EOF
#!/bin/sh
echo "I am an UPPER-case B"
EOF
$ cat > b <<EOF
#!/bin/sh
echo "I am a lower-case b"
EOF
$ chmod +x B b
$ ls
A.exe* B* a.exe* b* lower.c upper.c
$ ./B
I am an UPPER-case B
$ ./b
I am a lower-case b
Bug? Limitation? If it hurts, don't do that?
Yaakov
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