The man page for bash says: Enclosing characters in single quotes preserves the lit- eral value of each character within the quotes. A single quote may not occur between single quotes, even when pre- ceded by a backslash.
If I write the following bash script( test.bash ): #!/usr/bin/bash echo Argument is $1 If I execute this script in a directory that does NOT constain any perl (*.pl) files: test.bash '*.pl' I get as expected: Argument is *.pl However if there IS a perl file present I get: Argument is filename.pl BTW, I get exactly the same behavior if I use double quotes. Am I missing something here? I need to pass a literal pattern that may contain wildcard characters into a bash script and not have the shell expand it. Thanks. Lynn -- Unsubscribe info: http://cygwin.com/ml/#unsubscribe-simple Bug reporting: http://cygwin.com/bugs.html Documentation: http://cygwin.com/docs.html FAQ: http://cygwin.com/faq/
