I wrote: >O(k*2^(N/2))? It has to be faster than that by a counting argument. How much faster? -- Mike Stay Programmer / Crypto guy AccessData Corp. mailto:[EMAIL PROTECTED]
- rate of finding collisions staym
- Re: rate of finding collisions Matt Crawford
- Re: rate of finding collisions staym
- Re: rate of finding collisions Ian Goldberg
- Re: rate of finding collisions Paul Crowley
- Re: rate of finding collisions David Wagner
