No, because I'm looking to get all directories under the given path represented, as my example shows.
I do want the entire directory tree traversed, but I'm wanting only the number of top level objects in each directory reported as far as counts are for each directory. I appreciate your response. -----Original Message----- From: Bernhard Voelker <m...@bernhard-voelker.de> Sent: Monday, February 13, 2023 1:59 PM To: SCOTT FIELDS <scott.fie...@kyndryl.com> Cc: coreutils@gnu.org Subject: [EXTERNAL] Re: Getting inode counts from "du --inodes" clarification On 2/10/23 23:47, SCOTT FIELDS wrote: > I'm looking to get the number of files in each directory under a given path > > But only the top level of each directory (don't include files/directories > from > subdirectories in each processed directory) > > Example from your > statement: > > # du --inodes -d 0 --all /usr > 119613 /usr > > In this case, the number of entries directly within /usr is 15 (files, > directories, etc), but this is reporting all the files that exists within > /usr and all other subdirectories. > > A script that does what I mean is fairly simple but hardly a simple one > liner. > > -- > > for directory in $(find <directory> -type d); do echo "$(ls -a $directory \ > | sed '/^\.$/d;/^\.\.$/d'| wc -l) $directory"; done I see. du(1) traverses the whole directory hierarchy, so that's not wanted anyway. And --max-depth only changes which levels get printed and which not). One could of course try to work with an --exclude pattern, but that's awkward. Your direction with find(1) looks better - but with the -mindepth and -maxdepth option: find /usr -mindepth 1 -maxdepth 1 -printf x | wc -c 12 Does this come closer to what you want to achieve? Have a nice day, Berny
