Hi, If there is only one column in the input, then an out-of-range field spec will result in the print of the whole line.
$ cut -f 3 <<< $'a' | xxd 0000000: 610a a. Otherwise, an empty string is printed. $ cut -f 3 <<< $'a\tb' | xxd 0000000: 0a . This is counter-intuitive. I think that one-field input should not be treated specially. It should still result in no output for an out-of-range field spec. Is there a strong reason why `cut` should treat one-field input different? (What if users do want empty string be printed for out-of-range field even for one-field input?) Or this should be considered as a bug? -- Regards, Peng
