Re: Byte.parseByte throws NumberFormatException for value "95", radix: 16

[David Holmes]

Janda Martin said the following on 07/12/11 21:32:
I have question about parsing hex string. Java 6u25
When I call Byte.parseByte("95", 16) I get.

java.lang.NumberFormatException: Value out of range. Value:"95" Radix:16
        at java.lang.Byte.parseByte(Byte.java:153)

95 hex is 149 dec, Integer value '149' can be cast to valid byte value -107

Is the exception correct?

Yes. 95 hex == 149 dec which is > 127 and so is out of range for byte. 
If you want to use the bit pattern of 95 hex as a byte then you need to 
parse it as an int and do the cast yourself.

David Holmes

  Thank you very much for answer

 Martin JANDA
 jan...@crcdata.cz


Code from Byte.java

    public static byte parseByte(String s, int radix)
        throws NumberFormatException {
        int i = Integer.parseInt(s, radix);
        if (i < MIN_VALUE || i > MAX_VALUE)
            throw new NumberFormatException(
                "Value out of range. Value:\"" + s + "\" Radix:" + radix);
        return (byte)i;
    }