On Wed, Jul 11, 2012 at 9:52 PM, terry mcintyre <[email protected]> wrote: > From: Erik van der Werf <[email protected]> > >>On Wed, Jul 11, 2012 at 5:03 PM, terry mcintyre <[email protected]> >>wrote: >>> Am I misreading this? > >>yes, neither side can approach. Capturing in the big eyes give too >>many liberties. > > > Let's start with w e9 - b is in atari, but w has liberties at c7, g9, and e5 > - if b plays any of these, a b group is captured. > > b d11 captures the w rabbity six; w throws in at c12. b cannot make two eyes.
correct so far... > Nor can b play the other 3 liberties. wrong, White just has to make an approach move for each remaining shared liberty (i.e. capture a nakade) > whether b plays inside the upper right corner or passes, w kills the upper > right corner. No, White cannot kill any of the Black's groups. Trust me, even my program can solve this :-) White's liberty count after your first 3 moves is : 2 shared liberties +2 approach moves + 6-point eye filled with 5 stones = 11 liberties Black's weakest group has the same number of liberties, but Black has sente so he wins. Erik _______________________________________________ Computer-go mailing list [email protected] http://dvandva.org/cgi-bin/mailman/listinfo/computer-go
