On Mon, Mar 10, 2008 at 10:04:18PM -0400, Don Dailey wrote:
> Your method is to allocate 1 node when it's been visited once or twice -
> very natural I agree. My method is to allocate all the children at
> once, and wait until the parent has been visited some number of times
> (currently 100). If there are 50 legal moves, that gives on average
> about 1 node allocation every 2 visits, which is what you said you do.
I _expand_ 1 node when it's been visited twice, not allocate.
To clarify further:
...
if (tree_leaf_node(n)) {
if (n->playouts >= u->expand_p /* 2 */)
tree_expand_node(t, n, &b2);
/* Just now occured to me that I should probably
* descend to one of the children now yet. */
result = play_random_game(&b2, stone_other(color), u->gamelen);
break;
}
...
void
tree_expand_node(struct tree *t, struct tree_node *node, struct board *b)
{
tree_add_child(node, tree_init_node(pass));
for (int i = 1; i < t->board->size; i++)
for (int j = 1; j < t->board->size; j++)
if (board_atxy(b, i, j) == S_NONE)
tree_add_child(node, tree_init_node(coord(i,
j)));
}
--
Petr "Pasky" Baudis
Whatever you can do, or dream you can, begin it.
Boldness has genius, power, and magic in it. -- J. W. von Goethe
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