I'm not familiar with the tournament poker. So I may be wrong. shouldn't the 
'no.hands' in your formular be replaced with a single number that is the 
probability that oppenent's hand is better than me? If so,it factors out. The 
only scenarios left to be considered becomes (no. of my actions)^( no?my bids). 
Further, 'no. my bids' is an analytical function. It does not need to be 
treated as a discrete space. Otherwise to maximize a function in the interval 
[0,1] becomes infinitely complex.?


DL

-----Original Message-----
From: Tom Cooper <[EMAIL PROTECTED]>
To: computer-go <computer-go@computer-go.org>
Sent: Sat, 28 Jul 2007 6:42 am
Subject: Re: [computer-go] U. of Alberta bots vs. the Poker pros


At 02:58 28/07/2007, Arend wrote:?
?
?
>On 7/26/07, chrilly ><<mailto:[EMAIL PROTECTED]>[EMAIL PROTECTED]> wrote:?
>This is a remarkable result. I think poker is more difficult than Go and of?
>course chess.?
>?
>?
>I am as surprised by this statement as everyone else. Of course you >have to 
>develop some mixed strategies, try go guess implied pot >odds, folding equity 
>etc. but assuming you have access to a large >database of high level poker 
>games to analyze, why should it be that >hard, esp. in 2-person limit Hold'em??
>?
>Arend?
?
It seems plausible to me that poker should, in some sense, be more complicated 
than go. I'll ignore the massive savings from clever search tricks in both 
games. In order to get optimal play in go, it is necessary to search over all 
legal positions, of which there are fewer than 3^(19^2). In order to get 
optimal play (ie a Nash equilibrium) in poker, it is necessary to search over 
all strategies (of both players). A strategy is a map from your knowledge (the 
cards you can see and the opponent's bids) to an action. Even if we assume a 
single round of bidding, the number of strategies for a single player is 
roughly (no. of actions)^(no.hands * no opponents bids). This is massively 
higher than the number of go positions. ?
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