Just tested Mike's suggestion and "continue" does the trick.
Here's a test that verifies that..
NSArray *myStuff = [[NSArray alloc]initWithObjects:@"A", @"B", @"Puppies",
@"C",@"D", nil];
for (NSString *myThing in myStuff) {
if ([myThing isEqualToString:@"Puppies"]) {
continue;
}
NSLog(@"%@",myThing);
}
2015-05-14 12:19:10.422 test[6083:207] A
2015-05-14 12:19:10.423 test[6083:207] B
2015-05-14 12:19:10.423 test[6083:207] C
2015-05-14 12:19:10.424 test[6083:207] D
On May 14, 2015, at 12:15 PM, William Squires wrote:
> Not as far as I know; this is one of those times when you're better off doing
> a manual loop with a regular for( ; ; ) {} statement; then you can test the
> loop iterator with a switch() and take appropriate action (or none at all, if
> desired.)
>
> On May 14, 2015, at 11:09 AM, Alex Zavatone <z...@mac.com> wrote:
>
>> I'm sure this will sound like the noobiest question ever, but with Fast
>> Enumeration, if in an if statement within the loop, is there a way to stop
>> loop execution and essentially do a "proceed to the next item in the list
>> please"?
>>
>> Interested in something like BASIC's next repeat or something to that effect.
>>
>> In my scanning of the Apple docs, I didn't see that. Does break do that or
>> simply break out of the loop all together?
>>
>> For example, if I'm counting from 1 to 10, hit 3, I want the loop to skip to
>> 4 and keep going.
>>
>> Thanks much.
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