Have you tried just displaying an NSOpenPanel yourself then setting the
selected URL returned to the path control's URL property?
Sent from my iPhone
> On 2015/03/17, at 19:16, Jonathan Taylor <jonathan.tay...@glasgow.ac.uk>
> wrote:
>
> OK, I've got part of the way to a solution, but haven't got it fully working
> yet. Perhaps the weekday crowd here can advise?
>
> I've realised that I can get my path control to performClick:
>
> // When adding a new sequence we immediately prompt the user to select a
> folder to use for image files
> simulatingPathControlClick = true;
> [folderSelectPopup performClick:self];
> simulatingPathControlClick = false;
>
> This is a good start, because I see my delegate function being called:
>
> -(void)pathControl:(NSPathControl*)pathControl willPopUpMenu:(NSMenu*)menu
> {
> if (simulatingPathControlClick)
> {
> [menu performActionForItemAtIndex:0];
> }
> }
>
> This seems to be the only way of getting access to the menu
> (folderSelectPopup.menu always seems to return nil...). Now that I have
> access to the menu I can get it to performActionForItemAtIndex. That is
> basically what I'm trying to do here. However it doesn't quite work as it
> should. The code as written here brings up the Open dialog, which works as
> intended, but I am calling it sooner than I should (in willPopUpMenu; the
> menu has not yet popped up!). As a result, after the user dismisses the Open
> dialog, THEN the "choose" menu on the path control pops up, which is annoying
> and illogical for the user.
>
> If alternatively I wrap the performClick in a dispatch_async on the main
> thread (i.e. it should execute after the menu pops up) then something weird
> happens - the menu appears and then the Open dialog pops up (as I had hoped),
> but no file system items appear in there. I have a suspicion this has
> something to do with funny run-loop states when tracking menus, but I don't
> know what to do about it!
>
>
> I don't know if what I am trying to do is an appropriate way of going about
> things, but hopefully it gives a clearer idea of what I am trying to achieve
> here (bring up the Open dialog, just as if the user had selected "Choose..."
> themselves). And hopefully somebody can suggest how I should tweak what I am
> doing so it behaves correctly?
>
> Thanks again
> Jonny
>
>
>> On 15 Mar 2015, at 13:18, Jonathan Taylor <jonathan.tay...@glasgow.ac.uk>
>> wrote:
>>
>> I have a dialog which allows the user to select a folder containing data to
>> be processed, set various parameters that affect the processing, and
>> displays the result of the analysis. There is an NSPathControl (popup) to
>> select the folder. Inevitably the first thing the user does is choose a
>> folder (and of course they have the option of changing this later). I would
>> like to simplify the workflow by automatically popping up the "open" dialog
>> when the main dialog is first opened, as if the user has clicked on the path
>> popup and selected "choose". However, I can't work out an obvious way of
>> triggering the path control to behave as if the user has manually selected
>> "choose" from the popup.
>>
>> Is there a way I can do that? I could of course throw up my own "open"
>> dialog and programatically set the URL associated with the path control, but
>> that seems like unnecessary duplication of code when I could just call
>> something like [myPathControl displayChooseDialog] (if such a method
>> existed!).
>>
>> Can anyone suggest a way of doing what I want here?
>>
>> Thanks for any suggestions
>> Jonny
>
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