On Aug 28, 2013, at 10:26 PM, Dave <d...@looktowindward.com> wrote:
> NSCharacterSet *stopCharacters = [NSCharacterSet 
> characterSetWithCharactersInString:[NSString stringWithFormat:@"< 
> \t\n\r%C%C%C%C", 0x0085, 0x000C, 0x2028, 0x2029]];

Well, the %C expects a unichar (which is defined as another name for an 
unsigned short), while you are giving it 0x0085, which is a (signed) int. While 
you can mark a literal as an unsigned int by writing e.g. 0x0085U, there's no 
way to write a 'short' literal in C. So the best you can do is write the 
numbers as 

NSCharacterSet *stopCharacters = [NSCharacterSet 
characterSetWithCharactersInString:[NSString stringWithFormat:@"< 
\t\n\r%C%C%C%C", (unichar)0x0085U, (unichar)0x000CU, (unichar)0x2028U, 
(unichar)0x2029U]];

I.e. make them unsigned and typecast them to short. Using escape sequences 
instead as others have suggested is probably the better solution (then you can 
get rid of the entire -stringWithFormat: call as well and just write the whole 
string as one literal). This'll work as long as you are using a current version 
of the llvm compiler, I think. Older versions of the compilers included in 
Xcode didn't support the Unicode escape sequence as far as I remember.

Cheers,
-- Uli Kusterer
"The Witnesses of TeachText are everywhere..."
http://www.zathras.de


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