On 11 Mar 2013, at 20:45, Mike Abdullah wrote:
On 11 Mar 2013, at 20:33, Dave <d...@looktowindward.com> wrote:
On 11 Mar 2013, at 20:26, Mike Abdullah wrote:
I had assumed (and I thought I'd done something like this
before) that the:
myDict = [[super class] newDict];
statement would call newDict in BaseClass???? Instead it calls
the version in NewClass and goes into an infinite loop!!
Yes. [super class] calls super's implementation of the -class
method. You haven't overridden -class, so it does the same thing
as [self class].
People often make the same mistake in trying to do [super
respondsToSelector…
I'm guessing what you're really after is [[self superclass] newDict]
Thanks a Million, yes that's what I wanted!
There isn't a
-newDict
method defined, so how come I didn't get a complier error?
Because your code was still calling +newDict, just not on the class
you wanted.
I got a little confused by your code. Realise where I said -class
up above, that should actually be +class.
As others have pointed out [super newDict] might well be what you
want also/instead.
Confused now, I thought you meant +.
There is no instance of the class to call [super newDict] on?
There is no:
-NewDict method, just +newDict.
So, surely [super newDict] should error? Since I assume that super is
in this case a class not an object???
I want to call the class + method of the NewClass and have it call
the class + mehod of BaseClass?
Cheers
Dave
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