Le 18 juil. 2012 à 08:28, Rick Mann <rm...@latencyzero.com> a écrit :

> 
> On Jul 9, 2012, at 16:00 , John McCall wrote:
> 
>>>>> From: Rick Mann <rm...@latencyzero.com>
>>>>> Subject: ARC and reinterpret_cast?
>>>>> Date: July 7, 2012 9:13:29 PM PDT
>>>>> To: Cocoa-Dev List <cocoa-dev@lists.apple.com>
>>>>> 
>>>>> Hi. I'd like to write code like this:
>>>>> 
>>>>>   MyObject* foo = reinterpret_cast<__bridge MyObject*> (someVoidPointer);
>>>>> 
>>>>> But the compiler doesn't like it. It's perfectly happy with:
>>>>> 
>>>>>   MyObject* foo = (__bridge MyObject) someVoidPointer;
>>>>> 
>>>>> this is in a .mm file.
>>>>> 
>>>>> The error is:
>>>>> 
>>>>> error: type name requires a specifier or qualifier
>>>>>     MyObject* me = reinterpret_cast<__bridge MyObject*> (inRefCon);
>>>>>                                     ^
>>>>> error: expected '>'
>>>>>     MyObject* me = reinterpret_cast<__bridge MyObject*> (inRefCon);
>>>>>                                     ^
>>>>>> 
>>>>> note: to match this '<'
>>>>>     MyObject* me = reinterpret_cast<__bridge MyObject*> (inRefCon);
>>>>>                                    ^
>>>>> Is it a bug in the compiler, or am I doing something wrong? 
>> 
>> Well, it's definitely an ugly error message;  that's worth a bug.
>> 
>> The answer is that reinterpret_cast is redundant with __bridge.  Bridging
>> casts are essentially a different kind of named cast:  they document intent
>> more precisely than the general cast syntax, and they impose their own
>> well-formedness rules about the operand and result type.  So you're not
>> getting any extra safety here.
>> 
>> This is documented in the ARC specification:
>> http://clang.llvm.org/docs/AutomaticReferenceCounting.html#objects.operands.casts
>> 3.2.4. Bridged casts
>>  A bridged cast is a C-style cast annotated with . . .
>> 
>> In theory there's nothing preventing us from allowing these keywords on
>> named casts (although it would only be appropriate on reinterpret_cast),
>> but our sense is that doing so would only confuse the issue more by
>> suggesting subtle differences when none apply.
> 
> Well, more than anything, I wanted to keep consistent casting in my C++ code. 
> While (__bridge Foo*) might be well-specified, it doesn't look it from the 
> syntax. Maybe add bridge_cast<Foo*>()?
> 
> Thanks for the clarification, in any case.
> 

Just a though, but isn't it possible to define yourself a template function to 
do that ? 

something like 

template<class C>
static inline C bridge_cast(void *ptr) { return (__bridge C)ptr;  }

-- Jean-Daniel





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