On Mar 8, 2012, at 9:47 AM, Stephen J. Butler wrote:
> On Tue, Mar 6, 2012 at 8:19 PM, Marco Tabini <mtab...@me.com> wrote:
>>> I have an array and I am iterating through it using this technique:
>>>
>>>> for (id object in array) {
>>>> // do something with object
>>>> }
>>>
>>> Is there way to obtain the object's current array index position or do I
>>> have to add a counter?
>>
>> [array indexOfObject:object] should do the trick, though, if you need to do
>> it at every iteration, keeping a counter may be better.
>
> Here's a stupid question that occurred to me: do the documents
> anywhere guarantee that NSFastEnumeration over an NSArray will always
> return the items in order? That is, the first item returned will have
> index 0, second will have index 1, etc.
>
> I feel like the safe thing in this situation is to just revert back to
> an plain old "for (;;;)" loop. You know then that the index you have
> is the one for the object.
>
Yes. The documentation for NSArray guarantees that. Look at objectEnumerator
and the discussion following it.
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