The C99 spec I can find on the net has 6.5.13 (3) and (4). 

3. The && operator shall yield 1 if both of it's operands compare unequal to 0; 
otherwise it yields 0. The result has type int. 

4. Unlike the bitwise binary & operator, the && operator guarantees 
left-to-right evaluation; there is a sequence point after the evaluation of the 
first operand. If the firt operand compares equal to 0, the second operand is 
not evaluated. 

To my reading, and unless I have a totally bogus spec, that makes exactly the 
guarantee Jean-Daniel claims. 



On Aug 4, 2011, at 8:56, Graham Cox <graham....@bigpond.com> wrote:

> 
> On 04/08/2011, at 1:52 AM, Jean-Daniel Dupas wrote:
> 
>> One important difference for instance is that if you write if (a() & b()), 
>> both a() and b() will always be executed, while if you write if (a() && 
>> b()), b() will be executed only if a() is true.
> 
> 
> The C language doesn't make any guarantees about that. While this 
> optimisation is to be expected, the order of execution (left to right) and 
> the optimisation (b not executed) is implementation dependent.
> 
> This is a classic question for coding job interviews.
> 
> --Graham
> 
> 
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