On Aug 2, 2011, at 7:57 PM, Dale Miller wrote: > It is disconcerting that if A = 0x'0110' and B = '1001' then A & B returns > true but A && B returns 0, so "if (A && B)' is executed, the 'true' leg is > not taken
Don’t you have that backwards? Assuming B was supposed to be hex, i.e. 0x1001, then A & B would be 0, whereas A && B would be true. Charles_______________________________________________ Cocoa-dev mailing list (Cocoa-dev@lists.apple.com) Please do not post admin requests or moderator comments to the list. Contact the moderators at cocoa-dev-admins(at)lists.apple.com Help/Unsubscribe/Update your Subscription: http://lists.apple.com/mailman/options/cocoa-dev/archive%40mail-archive.com This email sent to arch...@mail-archive.com
