no. | is bitwise, not logical, || is the short-circuit one and there
is no ||=.
On Jun 23, 2009, at 7:56 PM, Graham Cox wrote:
Just a quickie...
If I have:
BOOL someValue = [object returnsBool];
someValue |= [anotherObject alsoReturnsBool];
is the second line subject to short-circuit evaluation? In other
words if the first method returns YES, is the second called?
--Graham
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