no. | is bitwise, not logical, || is the short-circuit one and there is no ||=.

On Jun 23, 2009, at 7:56 PM, Graham Cox wrote:

Just a quickie...

If I have:

BOOL someValue = [object returnsBool];

someValue |= [anotherObject alsoReturnsBool];

is the second line subject to short-circuit evaluation? In other words if the first method returns YES, is the second called?

--Graham


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