instead of [s isEqualToString:], you could use [s compare:]
On Fri, Jun 5, 2009 at 11:53 AM, Pierce Freeman <piercefreema...@comcast.net
> wrote:
> Hi KK:
>
> I was aware of this method to do so, but can this be done if you needed to
> search for, say, “Good” and wanted it to return Goodbye?
>
> Thanks for your help.
>
>
> On 6/5/09 8:50 AM, "KK" <kthem...@gmail.com> wrote:
>
> I'm not sure if this is what you're looking for, but Objective-C 2.0 has
> this:
>
> NSArray *a = [NSArray arrayWithObjects:@"Hello",@"Goodbye",nil];
>
> for (NSString *s in a) {
> if ([s isEqualToString:@"Goodbye"]) {
> NSLog(@"it is equal");
> }
> }
>
> And you can have an additional int (or NSInteger) counter to keep track of
> which object it is.
>
> Oh, you could also do [NSArray indexOfObject:]. if it returns NSNotFound,
> it's not in the array.
>
> On Fri, Jun 5, 2009 at 11:36 AM, Pierce Freeman <
> piercefreema...@comcast.net> wrote:
>
> Hi Everyone:
>
> I am most likely overlooking this function, but I just can't seem to find
> it
> in the documentation. I am looking for some way to search an NSArray
> listing for one string that is part of multiple objects in the array. This
> search then returns the number of objects that contained that string in it.
> I imagine this would be built into NSArray, so if anyone could steer me in
> the right direction, it would be greatly appreciated!
>
>
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