On Apr 12, 2009, at 9:21 PM, Michael Ash wrote:
On Sun, Apr 12, 2009 at 6:01 PM, John Joyce
<dangerwillrobinsondan...@gmail.com> wrote:
Is there an easy way to take input (user or file based) at runtime
and
convert unicode strings such as \u8D64 (UTF8 character) or a whole
series of
these to the human-readable characters they represent?
I imagine I should be using NSScanner, but is there not some simple
function
or method to lookup and return the character as it should be
represented?
Happy to RTFM, just need a pointer to the docs I should be looking
at.
Note that those are just unicode code points, not UTF-8 "characters",
whatever that would be. There is nothing built-in that I know of to
convert these.
You can search the string using one of the built-in methods, and then
read the number with NSScanner's -scanHexInt:. If you know that your
code points will always be no more than 4 digits (16 bits), which I
think would have to be the case because otherwise you wouldn't know
where to stop scanning the number, then you can make a string out of
it easily using the %C format specifier, like so:
unsigned value;
if([scanner scanHexInt:&value]) {
NSString *str = [NSString stringWithFormat:@"%C", value];
... put str back into the original string ...
}
else // couldn't parse the value
The above is failing to take into account the assumed knowledge that
the code points won't be more than 4 characters long. What if you
follow a \uNNNN sequence with characters (not intended to be part of
the \u sequence) in the [0-9a-fA-F] set? For example, "bar
\u0020foo". -scanHexInt: will take that to mean 0x20f. You'd need to
-scanCharactersFromSet:intoString: to read a sequence of hexadecimal
digits, then check the length and back up using -setScanLocation: if
it was more than 4 digits. Also, you'd truncate the resulting string
at 4 digits and scan _that_ using -scanHexInt:.
Regards,
Ken
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