I could be remembering wrong but I think you can append unichars to
mutable strings with [mstr appendFormat:@"%C", theunichar]. Or use %S
for a null terminated array of unichars.
On Mar 11, 2009, at 4:00 AM, Ken Thomases wrote:
If a string literal in your source code actually contains the \uNNNN
escape sequence, then that will be translated by the compiler. The
proper Unicode will end up in your binary. (This wasn't true with
earlier versions of gcc, but is true of the gcc that comes with
Xcode 3.x.) I suspect you know that.
If you actually get a string which contains the backslash, lowercase
'u', and hex digits, then you're going to have to parse that
somewhat manually. NSScanner will probably be helpful. Once you
get an integer from the hex digits, you can use NSString's character-
based methods like + stringWithCharacters:length: or -
initWithCharacters:length:. Sadly, I don't see a method on
NSMutableString for inserting or appending individual character
codes into a string.
Be mindful that not every UTF-16 code point is valid Unicode in
isolation. Combining characters and surrogate pairs complicate
things. I don't know if the character-based methods validate the
character sequence you provide to them. They might. So, you might
need to convert an entire string at once, rather than attempting to
just create an NSString from a single unichar derived from a \uNNNN
escape sequence. That single unichar may only be valid in
combination with the other characters around it.
Do you know the encoding of the rest of the string you're dealing
with? Is it guaranteed to be ASCII? Might it be UTF-8 which also
includes some escaped Unicode characters for some reason?
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