At 18:36 -0600 23/2/09, Ashley Perrien wrote:
This is relatively easy if I know how many arrays I'm working with
(3 in this case) to simply nest the for loops but if I don't know
how many arrays the primary array has, I can't think of a way to
nest the loops if I don't know how deeply to nest them. Any
suggestions on the best way to approach something like this?
You could use a simple recursion, something like this:
void Recurse( NSMutableArray* allresults, NSArray* arrays, int index,
NSMutableArray* current )
{
if ( index >= [arrays count] ) {
[allresults addObject:current];
} else {
for ( id obj in [arrays objectAtIndex:index] ) {
NSMutableArray* c = [current mutableCopy];
[c addObject:obj];
Recurse( allresults, arrays, index+1, c );
[c release];
}
}
}
void Doit()
{
// Initialize the 2D array
NSMutableArray *arrays = [NSMutableArray array];
[arrays addObject:[NSArray arrayWithObjects:@"1", @"2", @"3", nil]];
[arrays addObject:[NSArray arrayWithObjects:@"A", @"B", @"C", @"D", nil]];
[arrays addObject:[NSArray arrayWithObjects:@"Red", @"White", @"Blue", nil]];
NSMutableArray *allresults = [NSMutableArray array];
Recurse( allresults, arrays, 0, [NSMutableArray array] );
NSLog( @"%@", allresults );
}
Enjoy,
Peter.
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