On Mon, Feb 9, 2009 at 3:17 PM, Steve Sisak <sgs-li...@codewell.com> wrote:
> At 12:52 PM -0800 2/9/09, Clark Cox wrote:
>>
>> On Mon, Feb 9, 2009 at 12:10 PM, Sean McBride <s...@rogue-research.com>
>> wrote:
>>  > On 2/9/09 11:24 AM, Clark Cox said:
>>  >>That is, the preprocessor treats any undefined identifier in an '#if'
>>>>
>>>> or '#elif" as if it were defined to be zero.
>>>
>>  > I'm not a language lawyer, but I believe the latter is not guaranteed
>> to
>>>
>>>  evaluate to 0 if the macro is not defined.  However, I imagine 99% of
>>>  compilers will evaluate it to 0.  gcc certainly does.
>>
>> I am 100% positive that this is guaranteed by the standard:
>>
>>> From 6.10.1.3:
>>
>> "After all replacements due to macro expansion and the defined unary
>> operator have been performed, all remaining identifiers are replaced
>> with the pp-number 0"
>
> Just to be pedantic, which standard?
>
> You are definitely describing the behavior of the C++ preprocessor.
>
> IIRC, in ANSI C, #if of an undefined symbol is an error, and I'm not sure
> about C99.

It was the C99 standard that I was quoting above. The equivalent
passage from the C89/C90 standard:

"After all replacements are finished, the resulting preprocessing
tokens are converted into tokens, and then all remaining identifiers
are replaced with 0"

and the equivalent passage from the C++ standard:

"After all replacements due to macro expansion and thedefinedunary operator
have been performed, all remaining identifiers and keywords, except
for true and false, are
replaced with the pp-number 0"

> So, I belive #if defined(x) && (x) is good defensive programming.

Nope, it's still redundant. And I am 100% sure of that.

-- 
Clark S. Cox III
clarkc...@gmail.com
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