I would expect, at "A", for the timer to have any retain count of at
least one, and an equal number of releases pending in your
autorelease pool. Maybe the run loop's autorelease pool is getting
popped or drained as a side effect of adding the timer or something.
If you really want to figure it out, just make a trivial subclass of
NSTimer that implements retain, release, autorelease, and maybe
dealloc. Make them log, set breakpoints on them, take them apart and
see what makes them tick.
-Tom
On Mar 13, 2008, at 6:37 PM, Brian Greenstone wrote:
I'm hoping someone can shed some light on this for me. I'm getting
some unusual retainCount values from the following code:
NSTimer *theTimer;
theTimer = [NSTimer scheduledTimerWithTimeInterval:1.0
target: self
selector:
@selector(timerCallback)
userInfo: nil
repeats: YES];
NSLog(@"A: retain count: %i", [theTimer retainCount]);
[[NSRunLoop currentRunLoop] addTimer: theTimer forMode:
NSDefaultRunLoopMode];
NSLog(@"B: retain count: %i", [theTimer retainCount]);
The output I get is:
A: retain count: 2
B: retain count: 2
But that shouldn't be, right? Shouldn't the retainCount of
theTimer be 1 after scheduledTimerWithTimeInterval? Then shouldn't
it be bumped up to 2 after adding the timer to the Run Loop? It
appears that the retain count is starting at 2 which is wrong, and
then not being incremented by addtimer which is wrong. In the end
the count is still 2, so it is valid, but I'm confused why the
counts are doing this.
Thanks,
-Brian
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