(:t :t) is a function invocation. Clojure always attempts to invoke the
first element of a list as a function unless told not to, this is one of
the fundamental behaviours of a lisp.
In this case, clojure will attempt to invoke the keyword ":t" as a
function. Keywords are actually invokable in clojure, their behaviour is to
look themselves up in the specified collection.
For instance: (:t {:t "Here", :r "There"}) would return "Here".
In your example, the parameter is not a collection though, it's the same
keyword again, ":t". Attempting to do a collection look up using a
non-collection is defined to return nil.
Thus, (:t :t) -> nil
If you wish to create a structure by preventing clojure from using the
first element as a function, you must "quote" your example, ie, (quote (:t
:t)) or '(:t :t) then the structure would be a list with two elements.
--Aaron
On Mon, Dec 26, 2016 at 10:17 AM, Stuart Sierra <the.stuart.sie...@gmail.com
> wrote:
> As a moderator, I am posting this message on behalf of a new forum user,
> below. I have edited the message for appropriate language. –Stuart S.
>
>
> From: silver1 silver1 <silverzxh@...>
> Date: Mon, 26 Dec 2016 22:11:17 +0800
> Subject: I don't understand (:t :t)mean ,please help me !!
>
> hello,everyOne,i'm a new clojure learner.
> I don't know what the structure of (:t :t)!
> when i use coll? list? vector? set? map? seq? they all return false!!
> what is the structure of (:t :t)? thank you very much!
>
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