Hi everyone, I'm reading the excellent 'Functionnal programming for OO programmer' and I encounter an issue understanding how the '=' function works.
We have a 'Triangle' structure defined by a map of 'Point's so a Triangle is like {:point1 {:x 1 :y 1} :point2 {:x 1 :y 1} :point3 {:x 4 :y 2}} How does the '=' function actually evaluate the equality between 2 of this structure ? (= triangle1 triangle2). My guess : (= triangle1 triangle2) is like (= {:point1 {:x 1 :y 1} :point2 {:x 1 :y 1} :point3 {:x 4 :y 2}} {:point1 {:x 2 :y 3} :point2 {:x 1 :y 1} :point3 {:x 4 :y 2}}) then the evaluator might apply (= {:point1 {:x 1 :y 1} :point1 {:x 2 :y 3}), etc for the other points. But this looks like the 'map' function. I can't recreate the evaluator steps to get the equality between these values. Thanks you ! -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en --- You received this message because you are subscribed to the Google Groups "Clojure" group. To unsubscribe from this group and stop receiving emails from it, send an email to clojure+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.