As long as we're cutting out unnecessary code, this is also equivalent:
(defn baz [options]
(merge {:opt1 "default-1" :opt2 "default-2"} options))
(baz {:opt1 "custom-1" :opt3 "custom-3"});;=> {:opt3 "custom-3" :opt1 "custom-1
:opt2 "default-2"}
On Thursday, May 12, 2016 at 4:03:04 AM UTC-5, Dan Kersten wrote:
>
> Yes, only the first map passed into baz (only one passed in anyway in the
> example) is kept, anything else is thrown away. Seems like a strange
> example when something like this would have sufficed to get the point of
> merge across:
>
> (defn baz [options]
> (let [options (merge {:opt1 "default-1" :opt2 "default-2"}
> options)]
> options))
> (baz {:opt1 "custom-1" :opt3 "custom-3"});;=> {:opt3 "custom-3" :opt1
> "custom-1 :opt2 "default-2"}
>
>
> On Thu, 12 May 2016 at 07:45 hiskennyness <kent...@gmail.com <javascript:>>
> wrote:
>
>> I do not understand something this example:
>>
>>
>> https://clojuredocs.org/clojure.core/merge#example-54c7b859e4b0e2ac61831cdf
>>
>> Specifically:
>>
>> (defn baz [& options]
>>> (let [options (merge {:opt1 "default-1" :opt2 "default-2"}
>>> (first options))]
>>> options))
>>> (baz {:opt1 "custom-1" :opt3 "custom-3"});;=> {:opt3 "custom-3" :opt1
>>> "custom-1 :opt2 "default-2"}
>>>
>>>
>> IIANM, that throws away all but the first map in the rest parameter
>> options.
>>
>> Is there more going on here than I realize?
>>
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