Yes this could actually work thanks, I only need to iterate over all
the possible permutations of the first partition and combine it, still
certainly a lot less stuff to compute.
2015-10-05 12:08 GMT+01:00 Franklin M. Siler <m...@franksiler.com>:
> On Oct 5, 2015, at 0545, andrea crotti <andrea.crott...@gmail.com> wrote:
>
>> Any idea how to make this faster?
>> Other advices on the code are welcome as well..
>
> Why not generate the the possible left-hand teams and then cartesian product
> with the leftover players? E.g., if you want to match 2 on 2 and have
> players A B C D E:
>
> (A,B) cartesian product with (combinations #{C D E})
> (B,C) cartesian product with (combinations #{A D E})
> and so on with
> (C,D)
> (D,E)
>
> I think this will generate each possible match exactly twice- mirror images
> of each other, but proof is left as an exercise for the reader.
>
> I would imagine there is a better algorithm for this than mine.
>
> Cheers,
>
> Frank Siler
> Siler Industrial Analytics
> 314.799.9405
>
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