(for [[x y z] {:a "aa" :b "bb" :c "cc"}] [x y z])
([:c "cc" nil] [:b "bb" nil] [:a "aa" nil]) ;; WTF?
So her, I guess, your taking each entry in the map and destructuring them into
the three vars x, y, and z. Since each map entry is a pair, the third var z
will be nil.
Erik.
--
i farta
> Den 6. jun. 2015 kl. 13.24 skrev gvim <gvi...@gmail.com>:
>
>> On 06/06/2015 05:01, Sean Corfield wrote:
>> Page 84 is where it shows that maps are a sequence of pairs.
>>
>> The destructuring in James's code is on vectors -- the pairs in the
>> sequence.
>>
>> Hope that helps?
>>
>> Sean
>
> Page 84 describes the sequence abstraction in general but it's the implicit
> seq in for destructuring that threw me as I can't recall an example of it in
> any books I've read. I don't know what to make of this, for example:
>
> (seq {:a "aa" :b "bb" :c "cc"})
> ([:c "cc"] [:b "bb"] [:a "aa"]) ;; Fine so far
>
> (let [[x y z] (seq {:a "aa" :b "bb" :c "cc"})] [x y z])
> [[:c "cc"] [:b "bb"] [:a "aa"]] ;; Consistent with first example above
>
> (for [[x y z] {:a "aa" :b "bb" :c "cc"}] [x y z])
> ([:c "cc" nil] [:b "bb" nil] [:a "aa" nil]) ;; WTF?
>
> Taken together these make no sense to me.
>
> gvim
>
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